A body of mass m and radius R rolling horizontally without slipping at a speed v climbs a ramp to a height 3v24g. The rolling body can be:
The transnational, ½mv², and the rotational, ½Iw², energy is converted into potential energy, mgh,
so from law of conserve energy,
final = initial
mgh = ½mv² + ½Iw²
= ½mv² + ½Iv²/r²
Then h is
h = (1 + I/(mr²))v² /(2g)
h = 3v²/(4g) (from data )
so
(1 + I/(mr²))v² /(2g) = 3v²/(4g)
1 + I/(mr²) = 3/2
I = ½mr²
So it is a Sphere