A body of mass m hangs from three springs, each of spring constant K, as shown. If the mass is slightly displaced and released, the system will oscillate with time period

2 π \sqrt{\frac{m}{3 K}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 π \sqrt{\frac{3 m}{2 K}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 π \sqrt{\frac{2 m}{3 K}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 π \sqrt{\frac{3 K}{m}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $2 π \sqrt{\frac{3 m}{2 K}}$
$K_{eq} = \frac{K_{1} \times K_{2}}{K_{1} + K_{2}} = \frac{K \times 2 K}{K + 2 K} = \frac{2}{3} K$
$∴ T = 2 π \sqrt{\frac{m}{\frac{2 K}{3}}}$

Suggest Corrections

Similar questions

Q. A body of mass

^{'} m^{'}

hangs from three springs, each of spring constant

^{'} k^{'}

as shown in the figure. If the mass is slightly displaced and let go, the system will oscillate with time period

A particle of mass m is attached to three identical springs A, B and C each of force constant k as shown in figure. If the particle of mass m is pushed slightly against the spring A and released, the time period of oscillation is:

Q. A particle of mass m is attached to three identical springs A, B and C each of force constant k as shown in figure. If the particle of mass m is pushed slightly against the spring A and released, the time period of oscillation is:

Q. A mass M is suspended from a massless spring. An additional mass m stretches the spring further by a
distance x. The combined mass will oscillate with a period

Q. A body of mass

^{'} m^{'}

hangs from three springs, each of spring constant

^{'} K^{'}

as shown in the figure. If the mass is slightly displaced and let go, the system will oscillate with time period -

Join BYJU'S Learning Program

A body of mass m hangs from three springs, each of spring constant K, as shown. If the mass is slightly displaced and released, the system will oscillate with time period

The correct option is B 2π√3m2KKeq=K1×K2K1+K2=K×2KK+2K=23K ∴T=2π√m2K3

The correct option is B $2 π \sqrt{\frac{3 m}{2 K}}$
$K_{eq} = \frac{K_{1} \times K_{2}}{K_{1} + K_{2}} = \frac{K \times 2 K}{K + 2 K} = \frac{2}{3} K$
$∴ T = 2 π \sqrt{\frac{m}{\frac{2 K}{3}}}$