Question

# A body of mass m hits normally a rigid wall with velocity v and bounces back with the same velocity. The impulse experienced by the body is

A

$1.5mv$

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B

$2mv$

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C

zero

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D

$1mv$

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Solution

## The correct option is B $2mv$Step1: ImpulseWhen a large amount of force is exerted on a body in a very small time, then the force is called impulse.Impulse is defined as the change in momentum in a small-time, i.e, impulse, $∆p={p}_{f}-{p}_{i}$.Step2: Finding the impulseThe momentum of the body, when it hits the wall is ${p}_{i}=+mv$The momentum of the body, when it is bounced back is ${p}_{f}=-mv$Now change in momentum, $∆p=-mv-mv$or $∆p=-2mv$The impulse experienced by the body is $\mathbf{∆}\mathbit{p}\mathbf{=}\mathbf{-}\mathbf{2}\mathbit{m}\mathbit{v}$. So Option (B) is correct.

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