Question

A body of mass ‘m’ is accelerated uniformly from rest to a speed ‘V’ in a time ‘T’. The instantaneous power delivered to the body as a function time is given by

• A. $\frac{m{V}^2}{T^2}t$
• B. $\frac{m{V}^2}{T^2}{t}^2$
• C. $\frac{1}{2}\frac{m{V}^2}{T^2}{t}^2$
• D. $\frac{1}{2}\frac{m{V}^2}{T^2}t$

Answer 1

The correct option is A $\frac{m{V}^2}{T^2}t$

P = ma(v) Since v = aT
As v = at $\Rightarrow P=\frac{m{v}^2}{T^2}t$
$P=m{a}^{2}t$