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Question

A body of mass M is kept on a rough horizontal surface (friction coefficient = μ). A person is trying to pull the body by applying a horizontal force but the body is not moving. The force by the surface on A is F, where
(a) F = Mg
(b) F = μ Mg
(c) Mg ≤ F ≤ Mg 1+μ2
(d) Mg ≥ F ≥ Mg 1-μ2

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Solution

(c) Mg ≤ F ≤ Mg 1+μ2

Let T be the force applied on an object of mass M.

If T = 0, Fmin = Mg.

If T is acting in the horizontal direction, then the body is not moving.
T=μ(mg)

Fmax =(Mg)2+(T)2 =(Mg)2+(μMg)2

Thus, we have:
MgFMg1+(μ)2

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