A body of mass M is kept on a rough horizontal surface ( friction coefficient ). A person is trying to pull the body by applying a horizontal force but the body is not moving. The force by the surface on A is F where

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Solution

Since body is not moving
so $F =$ friction force
friction $=$ $μ N$ $(μ =$ coefficient of friction $)$
$= μ M g$
$s o F = μ M g .$
We get, $F = μ M g$

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A body of mass M is kept on a rough horizontal surface (friction coefficient = $μ$ ). A person is trying to pull the body by applying a horizontal force but the body is not moving. The force by the surface on the body is F, where

Q. A body of mass

M

is kept on a rough horizontal surface (friction coefficient

= μ

). A person is trying to pull the body by applying a horizontal force but the body is not moving. The force by the surface on

A

F

where:

Q. A body of mass M is kept on a rough horizontal surface (friction coefficient = μ). A person is trying to pull the body by applying a horizontal force but the body is not moving. The force by the surface on A is F, where
(a) F = Mg
(b) F = μ Mg
(c) Mg ≤ F ≤ Mg

\sqrt{1 + μ^{2}}

(d) Mg ≥ F ≥ Mg

\sqrt{1 - μ^{2}}

Q. A body of mass m is kept on a rough horizontal surface of friction coefficient m. A force P is applied horizontally, but the body is not moving. Find the net force F exerted by the surface on the body.

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A body of mass M is kept on a rough horizontal surface ( friction coefficient ). A person is trying to pull the body by applying a horizontal force but the body is not moving. The force by the surface on A is F where

Since body is not moving so F= friction forcefriction= μN (μ=coefficient of friction)=μMg soF=μMg.We get, F=μMg

Since body is not moving
so $F =$ friction force
friction $=$ $μ N$ $(μ =$ coefficient of friction $)$
$= μ M g$
$s o F = μ M g .$
We get, $F = μ M g$