wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

A body of mass M is kept on a rough horizontal surface (friction coefficient = μ). A person is trying to pull the body by applying a horizontal force but the body is not moving. The force by the surface on the body is F, where


A

F = Mg

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

F = μMg

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

Mg F Mg 1+μ2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

Mg F Mg 1+μ2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

Mg F Mg 1+μ2


If F1 = 0

So contact force will only have Normal which is equal to Mg
So F will be Mg

Now as F1 increases fr keeps increasing till it reaches limiting value i.e., μN = μ mg
So, in that case, contact force F will be

N2+fr2 = (Mg)2+(μMg)2

F = Mg 1+μ2

This means contact force F will lie between Mg F Mg 1+μ2


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Rubbing It In: The Basics of Friction
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon