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Question

A body of mass m is lunched up an a rough indines plane making an angle 45o with horizontal. If time of ascent is 13 of time of descent, the frictional coefficient between plane and body is

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Solution

tA=2SaA & tD=2SaD
tA=13tD
2Sgsinθ+μcosθ=132Sgsinθμgcosθ
9gsinθ9μgcosθ=gsinθ+μgcosθ
8gsinθ=10μgcosθ
810sinθcosθ=μ
μ=45tanθ (tan=45o)
So, μ=45 = 0.8

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