A body of mass m is moving in a circle of radius r with a constant speed v. The force on the body is $\frac{m v^{2}}{r}$ and is directed towards the centre. What is the work done by this force in moving the body over half the circumference of the circle

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Zero

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Solution

The correct option is B
Zero

Work done by centripetal force is always zero as the force and the instantaneous displacement are mutually perpendicular.

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A body of mass m is moving in a circle of radius r with a constant speed v. The force on the body is $\frac{m v^{2}}{r}$ and is directed towards the centre. What is the work done by this force in moving the body over half the circumference of the circle

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\frac{m v^{2}}{r}

is acting on the body towards the centre, then what will be the work done by this force in moving the body over half the circumference of the circle?

Q. A body of mass m is moving in a circle of radius

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\frac{m v^{2}}{r}

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(m v^{2} / r)

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A body of mass m is moving in a circle of radius r with a constant speed v. The force on the body is mv2rand is directed towards the centre. What is the work done by this force in moving the body over half the circumference of the circle

The correct option is B Zero Work done by centripetal force is always zero as the force and the instantaneous displacement are mutually perpendicular.

A body of mass m is moving in a circle of radius r with a constant speed v. The force on the body is $\frac{m v^{2}}{r}$ and is directed towards the centre. What is the work done by this force in moving the body over half the circumference of the circle

The correct option is B
Zero

Work done by centripetal force is always zero as the force and the instantaneous displacement are mutually perpendicular.