A body of mass M is resting on a rough horizontal plane surface- the coefficient of friction being equal to - At t-0- a horizontal force F-F0t starts acting on it- where F0 is a constant- Find the time T at which the motion starts-

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Standard XII

Physics

Limiting Friction

A body of mas...

Question

A body of mass M is resting on a rough horizontal plane surface, the coefficient of friction being equal to $μ$ . At t=0, a horizontal force $F = F_{0} t$ starts acting on it, where $F_{0}$ is a constant. Find the time T at which the motion starts?

μ M g / F_{0}

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M g / μ F_{0}

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μ F_{0} / M g

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None of these

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Solution

The correct option is A $μ M g / F_{0}$
When the value of F will becomes equal to the limiting friction then it will get into motion
so
$F_{0} t = μ M g$
$t = μ M g / F_{0}$

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A body of mass M is resting on a rough horizontal plane surface, the coefficient of friction being equal to μ. At t=0, a horizontal force F=F0t starts acting on it, where F0 is a constant. Find the time T at which the motion starts?

The correct option is A μMg/F0When the value of F will becomes equal to the limiting friction then it will get into motionsoF0t=μMgt=μMg/F0

A body of mass M is resting on a rough horizontal plane surface, the coefficient of friction being equal to $μ$ . At t=0, a horizontal force $F = F_{0} t$ starts acting on it, where $F_{0}$ is a constant. Find the time T at which the motion starts?

The correct option is A $μ M g / F_{0}$
When the value of F will becomes equal to the limiting friction then it will get into motion
so
$F_{0} t = μ M g$
$t = μ M g / F_{0}$