A body of mass m is situated at a distance 4R above the earth's surface, where R is the radius of earth. How much minimum energy be given to the body so that it may escape

mgR

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2mgR

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Solution

The correct option is B

Potential energy of the body at a distance 4R from the surface of earth

$U = - \frac{m g R}{1 + \frac{h}{R}} = - \frac{m g R}{1 + 4} = - \frac{m g R}{5}$

[As h = 4R (given)]

So minimum energy required to escape the body will be $\frac{m g R}{5}$ .

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A body of mass m is situated at a distance 4R above the earth's surface, where R is the radius of earth. How much minimum energy be given to the body so that it may escape

The correct option is B Potential energy of the body at a distance 4R from the surface of earth U=−mgR1+hR=−mgR1+4=−mgR5 [As h = 4R (given)] So minimum energy required to escape the body will be mgR5.

The correct option is B

Potential energy of the body at a distance 4R from the surface of earth

$U = - \frac{m g R}{1 + \frac{h}{R}} = - \frac{m g R}{1 + 4} = - \frac{m g R}{5}$

[As h = 4R (given)]

So minimum energy required to escape the body will be $\frac{m g R}{5}$ .