Question

A body of mass m kg is ascending on a smooth incline planeof inclination theta (sin theta = 1/x) with constant acceleration a m/s². the final velocity of the body is v m/s. The work done by the body during this motion is ?? (initial velocity of the body = 0)

Answer 1

$$\begin{gathered} Ifthebodyisoninclinedplane,thenthecomponentofgwillacttowardsmotionisg\sin \theta \\ soforceontheobjecttowardsdown=F=mg\sin \theta =\frac{mg}{x} \\ nowiftheobjecttraverseadis\tan ces \\ thenwecanwrite \\ {v}^2=u^2+2as \\ ors=\frac{v^2}{2a} \\ sotheworkdonebythebodyis=W=Fs=\frac{mg}{x}\times \frac{v^2}{2a}=\frac{mg{v}^2}{2ax} \end{gathered}$$