wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A body of mass m moves in a circular path with uniform angular velocity. The motion of the body has constant:

A
Acceleration
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Velocity
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Momentum
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Kinetic energy
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D Kinetic energy
In circular motion
v=w×r
Since in circular motion a body changes its direction continually and hence changes its radial vector
Now,
If angular velocity w is constant then for the different radial vector (r1,r2,r3) there will be different velocity of body (i.e.v1,v2,v3) as shown in figure
The centripetal acceleration of body will be to wards centre but for different position of body there will be different acceleration vector (a1,a2,a3) as shown in fig
momentum is given by
P=mv
Since velocity vector is changing
hence, P will change
In circular motion shown in figure
|r1|=|r2|=|r3|=r (radius of circle)
|v|=|w|r
Since r and |w| is constant therefore |v| is constant for any position of body
We know that kinectic energy (k)
k=12m|v|2
kinectic energy (k) of body will be constant

1432191_1023200_ans_f974810c47304a3d81a8a2a0c1d5f09c.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Centre of Mass in Galileo's World
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon