A body of mass $M$ moves in outer space with velocity $V$ . It is desired to break the body into two parts so that the mass of one part is one-tenth of the total mass. After the explosion, the heavier part comes to rest while the lighter part continues to move in the original direction of motion. The velocity of the small part will be

V

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(V / 2)

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(V / 10)

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10 V

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Solution

The correct option is D $10 V$
Let V be the velocity of one-tenth of original mass after the explosion.
due to momentum conservation, M×v = (9M/10)×0 + (M/10)×V
then V = 10×v

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The correct option is D 10VLet V be the velocity of one-tenth of original mass after the explosion.due to momentum conservation, M×v = (9M/10)×0 + (M/10)×Vthen V = 10×v

The correct option is D $10 V$
Let V be the velocity of one-tenth of original mass after the explosion.
due to momentum conservation, M×v = (9M/10)×0 + (M/10)×V
then V = 10×v