A body of mass $m$ moving at a constant velocity $v$ hits another body of the same mass moving at the same velocity but in the opposite direction and sticks to it. The common velocity after collision is

v

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 v

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{v}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $0$
Since the collision is inelastic, applying momentum conservation for inelastic collisions,
$m v + m (- v) = (m + m) V$
$V = 0$ .

Suggest Corrections

Similar questions

Q. A body of mass m moving at a constant velocity v hits another body of the same mass moving with a velocity v/2 but in the opposite direction and sticks to it. The common velocity after collision is

Q. a body of mass m moving with a constant velocity v hits another body of the mass m moving with same velocity v but in the opposite direction, and sticks to it. The velocity of the compound body after collision is :

Q. A body of mass m moving with a constant velocity V hits another body of the same mass moving with the same velocity V but in opposite direction and sticks to it. The velocity of the compound body after the collision is

A body of mass 'm' moving with a constant velocity 'v' hits another body of the same mass moving with the same velocity 'v' but in the opposite direction and sticks to it. The velocity of the compound body after collision is

A body of mass m moving with a constant velocity v hits another body of the same mass moving with the same velocity v but in the opposite direction and sticks to it. The velocity of the compound body after collision is

Join BYJU'S Learning Program

A body of mass m moving at a constant velocity v hits another body of the same mass moving at the same velocity but in the opposite direction and sticks to it. The common velocity after collision is

The correct option is B 0Since the collision is inelastic, applying momentum conservation for inelastic collisions,mv+m(−v)=(m+m)VV=0.

A body of mass $m$ moving at a constant velocity $v$ hits another body of the same mass moving at the same velocity but in the opposite direction and sticks to it. The common velocity after collision is

The correct option is B $0$
Since the collision is inelastic, applying momentum conservation for inelastic collisions,
$m v + m (- v) = (m + m) V$
$V = 0$ .