A body of mass m moving at a constant velocity v hits another body of the same mass moving with a velocity v/2 but in the opposite direction and sticks to it. The common velocity after collision is

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v/4

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v/2

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Solution

The correct option is B v/4
$\begin{matrix} P_{1}^{0} = i t \Rightarrow m v - \frac{m v}{2} = 2 m v^{1} \Rightarrow \frac{m v}{2} = 2 m v^{1} \Rightarrow v^{1} = \frac{v}{4} \end{matrix}$
Hence, option $B$ is the correct answer.

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A body of mass m moving at a constant velocity v hits another body of the same mass moving with a velocity v/2 but in the opposite direction and sticks to it. The common velocity after collision is

The correct option is B v/4P01=it⇒mv−mv2=2mv1⇒mv2=2mv1⇒v1=v4Hence, option B is the correct answer.

The correct option is B v/4
$\begin{matrix} P_{1}^{0} = i t \Rightarrow m v - \frac{m v}{2} = 2 m v^{1} \Rightarrow \frac{m v}{2} = 2 m v^{1} \Rightarrow v^{1} = \frac{v}{4} \end{matrix}$
Hence, option $B$ is the correct answer.