A body of mass $m$ moving with a speed $v$ suffers an inelastic collision with another body of mass $M = 2 m$ at rest. The speed of the composite body will be

$3 v$

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$\frac{v}{3}$

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$\frac{2 v}{3}$

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$\frac{3 v}{2}$

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Solution

The correct option is B
$\frac{v}{3}$

In an inelastic collision, the bodies stick together and gain a common velocity (say $v^{'}$ ). Applying conservation of linear momentum,
$m v + 2 m \times 0 = (m + 2 m) v^{'} \Rightarrow v^{'} = \frac{v}{3}$
Hence, the correct choice is (b).

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A body of mass m moving with a speed v suffers an inelastic collision with another body of mass M=2m at rest. The speed of the composite body will be

The correct option is B v3 In an inelastic collision, the bodies stick together and gain a common velocity (say v′). Applying conservation of linear momentum, mv+2m×0=(m+2m)v′⇒v′=v3 Hence, the correct choice is (b).

A body of mass $m$ moving with a speed $v$ suffers an inelastic collision with another body of mass $M = 2 m$ at rest. The speed of the composite body will be

The correct option is B
$\frac{v}{3}$

In an inelastic collision, the bodies stick together and gain a common velocity (say $v^{'}$ ). Applying conservation of linear momentum,
$m v + 2 m \times 0 = (m + 2 m) v^{'} \Rightarrow v^{'} = \frac{v}{3}$
Hence, the correct choice is (b).