A body of mass m rises to height $h = \frac{R}{5}$ from the earth's surface, where R is earth's radius. If g is acceleration due to gravity at earth's surface, the increase in potential energy is

mgh

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Solution

The correct option is C

$△ U = \frac{m g h}{1 + h R}$
Substituting $R = 5 h$ we get $△ U = \frac{m g h}{1 + \frac{1}{5}} = \frac{5}{6} m g h$

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A body of mass m rises to height h=R5 from the earth's surface, where R is earth's radius. If g is acceleration due to gravity at earth's surface, the increase in potential energy is

The correct option is C △U=mgh1+hR Substituting R=5h we get △U=mgh1+15=56mgh

A body of mass m rises to height $h = \frac{R}{5}$ from the earth's surface, where R is earth's radius. If g is acceleration due to gravity at earth's surface, the increase in potential energy is

The correct option is C

$△ U = \frac{m g h}{1 + h R}$
Substituting $R = 5 h$ we get $△ U = \frac{m g h}{1 + \frac{1}{5}} = \frac{5}{6} m g h$