A body of mass m slides down on an incline plane. It reaches at the bottom with a velocity v. If the same mass were in the form of the ring which rolls down this inclined, the velocity of the ring at the bottom’s
A
√2v
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B
1√2v
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C
v
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D
2v
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Solution
The correct option is B1√2v mgh=12mv212mR2×ω2+12mv2=mgh⇒v′=v√2