A body of mass m stands on end of a wooden plank of length L and mass M. The plank is floating on water. If the body walks from one end of the plank to the other end at a constant speed, the resulting displacement of the plank is given by :
A
MLm
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B
mlM
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C
(mlM+m)
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D
(MLM−m)
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Solution
The correct option is C(mlM+m) Refer to the given figure.
let x be distance of COM from center of plank, x=m∗l/2+M∗0m+M=ml2(m+M)
Since there are no external forces on plank-body system , COM of system will not change.
As seen from the figure center of plank shifted from ′x′ distance on one side to same distance on other side.
Total displacement will be "2x " =2×ml2(m+M)=ml(m+M)