A body of mass $m$ starts moving with velocity $V_{0}$ at point $A$ on a frictionless path as shown in the figure. The speed at point $C$ will be :

2 V_{0}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

V_{0}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{V_{0}}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{{V_{0}}^{2} + g h}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $\sqrt{{V_{0}}^{2} + g h}$
Given
Mass of body = m
Velocity of body at A = $V_{0}$
Velocity at C is =?
Solution
As total Magnetic energy remains conserved
Energy at A = Energy at C
$\frac{m (v_{0})^{2}}{2} + m g h = \frac{m v^{2}}{2} + m g \frac{h}{2}$
$v = ((v_{0})^{2} + g h)^{\frac{1}{2}}$
The correct option is option D

Suggest Corrections

Similar questions

Q. A point mass

m

moving with velocity

v_{0}

hits a ball of same mass

m

at rest elastically. After the collision, point mass moves with velocity

v_{0} / 2

at an angle

θ

from initial direction of motion. Then value of

θ

Q. A particle is thrown upwards with speed

v_{0}

. Find its speed when it reaches

2 / 3^{r d}

of the maximum height.

Q. In the figure shown, if the velocity of end A is

v_{0}

, find the velocity of the end

B

of the rigid rod at the given instant.

Q. A particle executing SHM with amplitude A has maximum velocity

v_{0}

. Its speed at displacement

\frac{A}{\sqrt{2}}

will be

A source of sound and a detector are placed at the same place on ground. At t = 0, the source S is projected towards reflector with velocity $V_{0}$ in vertically upward direction and reflector starts moving down with constant velocity $V_{0}$ . At t = 0, the vertical separation the reflector and source is $H (> \frac{v_{0}^{2}}{2 g})$ . The speed of sound in air is v(>> $v_{0}$ ). Take f₀ as the frequency of sound waves emitted by source. Based on above information answer the following questions.

Join BYJU'S Learning Program

A body of mass m starts moving with velocity V0 at point A on a frictionless path as shown in the figure. The speed at point C will be :

The correct option is D √V02+ghGivenMass of body = mVelocity of body at A = V0Velocity at C is =?SolutionAs total Magnetic energy remains conservedEnergy at A = Energy at Cm(v0)22+mgh=mv22+mgh2v=((v0)2+gh)12The correct option is option D

A body of mass $m$ starts moving with velocity $V_{0}$ at point $A$ on a frictionless path as shown in the figure. The speed at point $C$ will be :