The correct option is D depends on both horizontal and vertical components of displacement.
Let the work done by the force F be WF.
Work done by the friction force on the rough hill, WFriction=−μmgs
where s is displacement along the surface of the hill.
Work done by gravity force, WG=−mgh
Apply Work-Energy theorem:
WF+WG+WFriction=ΔKE
(∵ the block is slowly hauled, final and initial velocity = 0)
WF−mgh−μmgs=0
WF=mgh+μmgs
Hence it depends on horizontal and vertical components of displacement.