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Question

A body of mass M was slowly hauled up a rough hill by a force F which at each point was directed along a tangent to the path of the hill. The work done by this force


A
depends on vertical component only.
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B
does not depend on coefficient of friction.
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C
depends on horizontal component only.
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D
depends on both horizontal and vertical components of displacement.
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Solution

The correct option is D depends on both horizontal and vertical components of displacement.
Let the work done by the force F be WF.
Work done by the friction force on the rough hill, WFriction=μmgs
where s is displacement along the surface of the hill.
Work done by gravity force, WG=mgh

Apply Work-Energy theorem:
WF+WG+WFriction=ΔKE
( the block is slowly hauled, final and initial velocity = 0)
WFmghμmgs=0
WF=mgh+μmgs
Hence it depends on horizontal and vertical components of displacement.

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