A body of mass ' $M$ ' when hung on a spiral spring, the spring stretches by $20 c m$ , when it is pulled down and released its period of oscillation is

\frac{2 π}{5}

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\frac{2 π}{7}

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\frac{2 π}{3}

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2 π

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Solution

The correct option is A $\frac{2 π}{7}$
$M g = k (20) \times 10^{- 2}$
$k = 5 m g$
$T = 2 π \sqrt{\frac{M}{k}}$
$T = 2 π \sqrt{\frac{M}{5 \times M g}}$
$T = 2 π \sqrt{\frac{1}{5 g}}$
$T = \frac{2 π}{7}$

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A body of mass 'M' when hung on a spiral spring, the spring stretches by 20 cm, when it is pulled down and released its period of oscillation is

The correct option is A 2π7Mg=k(20)×10−2k=5mgT=2π√MkT=2π√M5×MgT=2π√15gT=2π7

A body of mass ' $M$ ' when hung on a spiral spring, the spring stretches by $20 c m$ , when it is pulled down and released its period of oscillation is

The correct option is A $\frac{2 π}{7}$
$M g = k (20) \times 10^{- 2}$
$k = 5 m g$
$T = 2 π \sqrt{\frac{M}{k}}$
$T = 2 π \sqrt{\frac{M}{5 \times M g}}$
$T = 2 π \sqrt{\frac{1}{5 g}}$
$T = \frac{2 π}{7}$