Question

A body of mass $\text{m}$ starts from rest, and attains a final velocity of ${\text{v m s}}^{-1}$ in a duration of $\text{t}$, with uniform acceleration. If the net force acting on the bus is given by $\text{F}$, then:

• A. $\text{v}=\frac{\text{mF}}{\text{t}}$
• B. $\text{m}=\frac{\text{Fv}}{\text{t}}$
• C. $\text{v}=\frac{\text{Ft}}{\text{m}}$
• D. $\text{F}=\text{mtv}$

Answer 1

The correct option is C $\text{v}=\frac{\text{Ft}}{\text{m}}$

According to Newton's second law of motion, a net unbalanced force acting on a body accelerates (or decelerates) the body. In other words, if the body of mass $\text{m}$ is acted upon by a net unbalanced force of $\text{F}(\ne 0)$, then the acceleration caused in the body is given by $\text{a}=\frac{\text{F}}{\text{m}}$ or $\text{F = ma}$
Acceleration of a body is the change in the velocity of the body with time. So, $\text{a}=\frac{\Delta \text{v}}{\text{t}}$
Where the change in the velocity, $\Delta \text{v}$ = final velocity - initial velocity
In this case, the body started from rest, so its initial velocity = 0
and final velocity = $\text{v}$
Therefore, $\text{F =}\frac{\text{mv}}{\text{t}}$ or $\text{v =}\frac{\text{Ft}}{\text{m}}$