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Question

A body of volume V and density ρ is initially submerged in a liquid of density ρ. If it lifted through a height h in the liquid, its potential energy will:

A
increase by hV(ρρ)g
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B
decrease by hV(ρρ)g
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C
increase by hVρg/ρ
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D
decrease by hVρg/ρ
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Solution

The correct option is A increase by hV(ρρ)g
Buoyant force(FB)=ρvg
Fnet=ρvgFB
=ρvgρg
=(ρρ)vg
work done in lifting the body upto height 'h'
ω=Fs=FScosθ=Fnethcos(180o)
ω=Fneth
ω=(ρρ)vg
since, change in potential energy (ΔU):
ΔU=(Δω)
So,
ΔU=ω=[(ρρ)vg]
ΔU=(ρρ)vg
So,
Increase in potential energy by (ρρ)vg.

1180585_1208918_ans_65ea74362d894e4a9ec727fdd0bf6db7.jpg

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