Question

A body of weight $2kg$ is suspended as shown in the figure The tension $T_1$ in the horizontal string (in kg wt) is

Answer 1

The tension in the above string can be divided into two components where the component opposite to weight will balance the weight while the component of this tension opposite to $T_1$ will be equal to $T_1$ .

$T\sin \theta =2kgwt$

$T\cos \theta =T_1$

The first equation gives

$T=4kgwt$

So $T_1$ will be,

$T_1=2\sqrt{3}kgwt$