A body of weight 50 N is floating in the water. Find its apparent weight?

10 N

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20 N

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50 N

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0 N

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Solution

The correct option is D
0 N

When a body floats in a liquid, it experiences two forces on it, i.e, its weight acting downwards and the buoyant force exerted by liquid upwards.

Apparent weight is the difference between these two forces and during floating apparent weight is zero because both of the forces are equal which makes the net force equal to zero.

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Similar questions

A body of mass $2 k g$ is moving with an acceleration of $10 m / s^{2}$ . The net force acting on the body is

A body of weight W is floating in a liquid. Its apparent weight will be :
(a) equal to W

(b) less than W
(c) greater than W

(d) zero.

How is the apparent weight of the floating body 0?

The apparent weight of the floating body is zero.

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