1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard IX
Physics
Net Force
- Question 7:...
Question
Question 7: A body of weing W is suspended from the ceiling of a room through a rope of weight R. the ceiling pulls the rope by a force of
Open in App
Solution
The ceiling pulls the chain with a force equal to the sum of weights of rope and the body.
So the pulling force = (W + R)
Hope I could be of help
Thank you
Suggest Corrections
3
Similar questions
Q.
A body of weight
W
1
is suspended from the ceiling of a room through a chain of weight
W
2
. The ceiling pulls the chain by a force equal to:
Q.
A mass of
10
k
g
is suspended by a rope of length
2.8
m
from a ceiling. A force of
98
N
is applied at the midpoint of the rope as shown in the figure. The angle made by rope with the vertical in equlibrium is
Q.
A mass of
6
k
g
is suspended by a rope of length
2
m
from a ceiling. A force of
50
N
is applied in horizontal direction at the mid point of the rope. What is the angle of the rope with the vertical in equilibrium?
Q.
A uniform rope of mass
m
hangs freely from a ceiling. A monkey of mass
M
climbs up the rope with an acceleration
a
. The force exerted by the rope on the ceiling is
Q.
A mass of
6
k
g
is suspended by a rope of length
2
m
from the ceiling. A force of
50
N
horizontally is applied at the mid point
P
of the rope. Calculate the angle of rope makes with the vertical. Neglect the mass of rope.
(
g
=
9.8
m
s
−
2
)
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Basics
PHYSICS
Watch in App
Explore more
Net Force
Standard IX Physics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app