MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

KE & PE Graph

A body perfor...

Question

A body performs SHM along the straight line segment ABCDE with C as the mid point of segment AE (A and E are the extreme position for the SHM). Its kinetic energies at B and D are each one-fourth of its maximum value. If length of segment AE is 2R, then the distance between B and D is :- (1) dfrac{{sqrt 3 }}{2}R (2) dfrac{R}{{sqrt 2 }} (3) sqrt 3 R (4) sqrt 3 ,R

Open in App

Solution

Suggest Corrections

thumbs-up

5

Similar questions

Q. A body performs harmonic oscillations along the straight line

A B C D E

C

as a mid-point. of

A E

. Its kinetic energies at

B

D

are each one-fourth of its maximum value. If

A E = 2 R

, the distance between

B

D

Q. A body performs SHM along the straight line ABCDE with C is the midpoint of AE. Its kinetic energies at B and D are each one-fourth of its maximum value. If AE = 2A, then the distance between B and D is:

Q. A body performs simple harmonic oscillations along the straight ABCDE with C as the midpoint of AE.Its kinetic energies at B and D are each one fourth of its maximum value.If AE=2R the distance between B and D is

Q. A particle performs SHM of amplitude

A

along a straight line. When it is at a distance

\frac{\sqrt{3}}{2} A

from mean position, its kinetic energy gets increased by an amount

\frac{1}{2} m ω A^{2}

due to an impulsive force. Then its new amplitude becomes.

Q. A particle performs S.H.M of amplitude A along a straight line. When it is at a distance

\frac{\sqrt{3}}{2} A

from mean position, its kinetic energy gets increased by an amount

\frac{1}{2} m ω^{2} A^{2}

due to an impulsive force. Then its new amplitude becomes

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Energy in SHM

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon