A body possessing kinetic energy T moving on a rough horizontal surface is stopped in a distance y. The frictional force exerted on the body is:

T y

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\frac{\sqrt{T}}{y}

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\frac{T}{y}

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\frac{T}{\sqrt{y}}

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Solution

The correct option is C $\frac{T}{y}$
Energy loss due to friction = $f_{k} . y$
And it should be equal to T
$= f_{k} . y = T$
$∴ f_{k} = \frac{T}{y}$

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A body possessing kinetic energy T moving on a rough horizontal surface is stopped in a distance y. The frictional force exerted on the body is:

The correct option is C TyEnergy loss due to friction = fk.y And it should be equal to T=fk.y=T∴fk=Ty

The correct option is C $\frac{T}{y}$
Energy loss due to friction = $f_{k} . y$
And it should be equal to T
$= f_{k} . y = T$
$∴ f_{k} = \frac{T}{y}$