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Byju's Answer

Standard IX

Physics

Freefall & Motion

A body projec...

Question

A body projected up reaches a point $A$ in its path at the end of $4^{t h}$ second and reaches the ground after $5$ seconds from the start. The height of $A$ above the ground is ( $g = 9.8 m / s^{2}$ )

19.6 m

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30.6 m

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11 m

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25 m

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Solution

The correct option is A $19.6 m$

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A body projected up reaches a point A in its path at the end of 4th second and reaches the ground after 5 seconds from the start. The height of A above the ground is (g=9.8m/s2)

The correct option is A 19.6m

A body projected up reaches a point $A$ in its path at the end of $4^{t h}$ second and reaches the ground after $5$ seconds from the start. The height of $A$ above the ground is ( $g = 9.8 m / s^{2}$ )

The correct option is A $19.6 m$