A body projected upwards with an initial velocity of $49 \frac{m}{s}$ . What will be its final velocity after 3 seconds? [acceleration due to gravity $g = 9.8 \frac{m}{s^{2}}$ ]

$19.6 \frac{m}{s}$

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$29.4 \frac{m}{s}$

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$9.8 \frac{m}{s}$

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$39.2 \frac{m}{s}$

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Solution

The correct option is A
$19.6 \frac{m}{s}$

Given initial velocity, $u = 49 \frac{m}{s}$

Acceleration, $a = - 9.8 \frac{m}{s^{2}}$ [Since body is projected upwards]

Time $t = 3 s$

Final velocity, $v = u + a t$

$v = 49 + (- 9.8 \times 3)$

$v = 49 - 29.4$

$v = 19.6 \frac{m}{s}$

Velocity after 3 seconds = $19.6 \frac{m}{s}$

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A body projected upwards with an initial velocity of 49ms. What will be its final velocity after 3 seconds? [acceleration due to gravity g=9.8ms2]

The correct option is A 19.6ms Given initial velocity, u=49ms Acceleration, a=−9.8ms2 [Since body is projected upwards] Time t=3s Final velocity, v=u+at v=49+(−9.8×3) v=49−29.4 v=19.6ms Velocity after 3 seconds = 19.6ms

A body projected upwards with an initial velocity of $49 \frac{m}{s}$ . What will be its final velocity after 3 seconds? [acceleration due to gravity $g = 9.8 \frac{m}{s^{2}}$ ]