A body projected vertically upwards takes 3 seconds to reach the highest point. Calculate the velocity with which it was projected,. $g = 9.8 \frac{m}{s^{2}} .$

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Solution

Step 1: Given:
Final velocity (v)=0.
Time (t)=3 s.
Acceleration a= - g and $g = 9.8 \frac{m}{s^{2}} .$
Step 2: Formula
v=u+at
Step 3:Calculation.
Velocity with which it is thrown is v=u+at.
$0 = u - g \times 3 u = 3 g u = 3 s \times 9.8 \frac{m}{s^{2}} . u = 29.4 \frac{m}{s} .$
Hence, the velocity with which it is thrown is $u = 29.4 \frac{m}{s} .$

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A body projected vertically upwards takes 3 seconds to reach the highest point. Calculate the velocity with which it was projected,.g=9.8ms2.

Step 1: Given:Final velocity (v)=0.Time (t)=3 s.Acceleration a= - g and g=9.8ms2.Step 2: Formula v=u+atStep 3:Calculation.Velocity with which it is thrown is v=u+at.0=u-g×3u=3gu=3s×9.8ms2.u=29.4ms.Hence, the velocity with which it is thrown is u=29.4ms.

A body projected vertically upwards takes 3 seconds to reach the highest point. Calculate the velocity with which it was projected,. $g = 9.8 \frac{m}{s^{2}} .$