A body released from a great height falls freely towards the earth.Another body is released from the same height exactly one second later. The separation between both the bodies two seconds after the release of the second body is

a) 24.5 metre

b)34.5 metre

c) 44.5 metre

d) 54.5 metre

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Solution

Displacement of the first body after 3 seconds= S = ut + ½ g t^2 = 44.1m/s

Displacement of the first body after 2 seconds= S = ut + ut + ½ g t^2 = 19.6m/s

The separation between them=44.5 - 19.6 = 24.5m/s

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A body released from a great height falls freely towards the earth.Another body is released from the same height exactly one second later. The separation between both the bodies two seconds after the release of the second body is a) 24.5 metre b)34.5 metre c) 44.5 metre d) 54.5 metre

Displacement of the first body after 3 seconds= S = ut + ½ g t^2 = 44.1m/s Displacement of the first body after 2 seconds= S = ut + ut + ½ g t^2 = 19.6m/s The separation between them=44.5 - 19.6 = 24.5m/s

A body released from a great height falls freely towards the earth.Another body is released from the same height exactly one second later. The separation between both the bodies two seconds after the release of the second body is

a) 24.5 metre

b)34.5 metre

c) 44.5 metre

d) 54.5 metre

Displacement of the first body after 3 seconds= S = ut + ½ g t^2 = 44.1m/s

Displacement of the first body after 2 seconds= S = ut + ut + ½ g t^2 = 19.6m/s

The separation between them=44.5 - 19.6 = 24.5m/s