The correct option is D √2gh
∵ Total mechanical energy is conserved
Initial K.E + Initial P.E = Final K.E + Final P.E
So, the sum of kinetic energy (KEA) and potential energy (PEA) at point A will be equal to the sum of kinetic energy (KEC) and potential energy (PEC) at point C
⇒KEA+PEA=KEC+PEC
⇒0+mgh=12mv2C+0 [∵vA=0 So KEA=0 and base of incline is taken as reference]
⇒vC=√2gh
Velocity at point C is √2gh.