The correct option is A only if α is greater than the angle of friction
Consider a block placed on a rough horizontal plane. Now, the reaction force →R is because it is equal and opposite to the weight −→W . If the force →F is applied to the block towards the plane at an angle θ, the resolved forces will act along vertical and horizontal direction.
The horizontal component of force Fsinθ have to overcome the frictional force so that the block just begins to slide. Frictional force is equal to limiting friction Flimiting, when this condition is satisfied the angle of applied force θ will be greater than angle of friction ϕ and block can move along the plane.