Question

A body revolves with constant speed v in a circular path of radius r . the magnitude of its average acceleration during motion between two points in diametrically opposite direction is:

• A. Zero
• B. $\frac{v^2}{r}$
• C. $\frac{2v^2}{\pi r}$
• D. $\frac{v^2}{2r}$

Answer 1

The correct option is C $\frac{2v^2}{\pi r}$

The correct option is C.

The acceleration will change as there is change in the velocity at any direction

As we know that

$T=\frac{2\pi r}{v}$

$\frac{T}{2}=\frac{\pi r}{v}=t$

$a=\frac{v(-v)}{t}$

$a=\frac{2v}{t}$

$a=\frac{2v^2}{\pi r}$