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Finding Average Velocity

A body rises ...

Question

A body rises vertically up to a height of 125 m in 5 s and then comes back at the point of projection. Find the average speed
Given, s= 125 m, t=5 s

25 m / s

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125 m / s

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5 m / s

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50 m / s

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Solution

The correct option is D $25 m / s$
Average speed $= \frac{Total distance travelled}{Total time of journey}$
$= \frac{2 s}{2 t} = \frac{250 m}{10 s}$
$= 25 m / s$

Suggest Corrections

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125 m

5 s

v (t) = t^{2} - 5 t m/s

10 sec

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V_{2} = 4 m/s

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h = 10 m

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(s)

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