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Question

A body rotating with 20 rad/s is acted upon by a uniform torque providing it an angular deceleration of 2 rad/s2. At which time will the body have kinetic energy same as the initial value if the torque acts continuously?

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Solution

Given,

Equal kinetic energy

12Iω21=12Iω22

ω2=±ω1

Possible value is ω2=ω1

Initial angular velocity, ω1=20rad/s

Final velocity, ω2=20rad/s

Angular acceleration α= 2rad/s2

ω2=ω1+αt

t=ω2ω1α=20202=20sec

After 20sec, it again achieves equal kinetic energy.


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