A body slides down a frictionless track which ends in a circular loop of diameter $D$ . Then the minimum height h of the body in terms of $D$ so that it may just complete the loop, is

h = \frac{5 D}{2}

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h = \frac{5 D}{4}

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h = \frac{3 D}{4}

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h = \frac{D}{4}

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Solution

The correct option is B $h = \frac{5 D}{4}$
Correct Option (b) h = 5D/4

Explanation:

We know h = (5/2) r = 5/2 (D/2) = 5D/4

[For critical condition of vertical looping]

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A body slides down a frictionless track which ends in a circular loop of diameter D. Then the minimum height h of the body in terms of D so that it may just complete the loop, is

The correct option is B h=5D4Correct Option (b) h = 5D/4 Explanation:We know h = (5/2) r = 5/2 (D/2) = 5D/4[For critical condition of vertical looping]

A body slides down a frictionless track which ends in a circular loop of diameter $D$ . Then the minimum height h of the body in terms of $D$ so that it may just complete the loop, is

The correct option is B $h = \frac{5 D}{4}$
Correct Option (b) h = 5D/4

Explanation:

We know h = (5/2) r = 5/2 (D/2) = 5D/4

[For critical condition of vertical looping]