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Question

A body slides down a rough inclined plane of inclination θ with constant velocity v. If it is projected up the plane with velocity 2v, then it moves up the plane with

A
constant velocity
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B
retardation g sin θ
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C
retardation 2gsin θ
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D
acceleration g sin θ
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Solution

The correct option is D retardation 2gsin θ
It is sliding down with constant velocity v, friction f=mgsinθ
When ball is projected upward f and mgsinθ will act in same direction (i.e backward direction)
So retardation of body is f+mgsinθm=2gsinθ

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