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Question

A body sliding down at an angle theta to the horizontal. then coefficient of friction is equal to

A
sinθ
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B
cosθ
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C
tanθ
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D
cotθ
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Solution

The correct option is C tanθ
From free body diagram,
N=mgcosθ. . . . . . . .(1)
fr=mgsinθ
μ.N=mgsinθ
μ.mgcosθ=mgsinθ (from equation 1)
μ.cosθ=sinθ
μ=sinθcosθ
μ=tanθ
The correct option is C.


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