Question

A body slipping on a rough horizontal plane moves with a deceleration of 4.0 $m/s^2$ With a deceleration of kinetic friction between the block and the plan?

Answer 1

Let m = mass of the block.

From the freebody diagram,
$\text{R - mg = 0}\Rightarrow \text{R - mg = 0}\text{Again}\text{ma}-\mu R=0$
or $\text{ma}=\mu R$
From Equation (i), $ma=u\mu g$
$\Rightarrow a=\mu g\Rightarrow 4=\mu g\mu =\frac{4}{g}=\frac{4}{10}=0.4$
Hence th co-efficient of kinetic friction between the block and the plane is 0.4