wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A body started with velocity of 20 ms1 and moving with an acceleration of 2 ms2. The distance travelled by the body in the 8th second is

A
35 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
20 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
45 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
30 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 35 m
Given, u=20 ms1, a=2 ms2, n=8
As we know that the distance travelled by a particle in nth second is given as
sn=u+12a(2n1)
s8th=20+12×2(2×81)
s8th=20+15
s8th=35 m

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Motion Under Constant Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon