Question

A body starting from rest and travelling with uniform acceleration has a velocity of $40m{s}^{-1}$ after $10$ second at A. Velocity of the body $4$ second before it crosses the point A is :

• A. 16 $m{s}^{-1}$
• B. 20 $m{s}^{-1}$
• C. 24 $m{s}^{-1}$
• D. 32 $m{s}^{-1}$

Answer 1

Answer: (C)

24 $m{s}^{-1}$

$v=u+at$
$40=a\times 10\Rightarrow a=4m/s^2$
So, velocity after $(10-4)=6sec\Rightarrow v^{\prime }$
$v^{\prime }=u+at=4\times 6=24m/s$