Given, initial velocity, u=0 ms−1 and acceleration, a=10 ms−2
From the first equation of motion, we have, v=u+at
Velocity after 10 seconds is
v=0+10×10 =100 ms−1
Now we have to find the displacement between 10 to 15 seconds
In this case, initial velocity, u=100 ms−1
Time taken, t=15−10=5 s
Let 's' be the displacement.
From the second equation of motion, we have,
s=ut+12at2
⇒s=100×5+12×10×52
⇒s=500+125=625 m