A body starts from rest and moves with a constant acceleration of 4m-s2- Calculate the velocity acquired by it after it has covered a distance of 8 m-

Step 1: Given thatInitial velocity = 0Acceleration = 4m/s^2.Distance= 8 m.Step 2: Formulav^2 u^2=2as.Step 3: Calculationv^2 u^2=2as.v^2 0=2× 4m/s^2× 8m .0ex0ex ...

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Standard XII

Physics

Uniform and Non Uniform

A body starts...

Question

A body starts from rest and moves with a constant acceleration of 4 $\frac{m}{s^{2}}$ . Calculate the velocity acquired by it after it has covered a distance of 8 m.

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Solution

Step 1: Given that
Initial velocity = 0
Acceleration = 4 $\frac{m}{s^{2}}$ .
Distance= 8 m.
Step 2: Formula
$v^{2} - u^{2} = 2 a s .$
Step 3: Calculation
$v^{2} - u^{2} = 2 a s .$
$v^{2} - 0 = 2 \times 4 \frac{m}{s^{2}} \times 8 m . v^{2} = 64 . v = \sqrt{64 .} v = 8 \frac{m}{s} .$
Step 4:
Hence, Velocity = $8 \frac{m}{s} .$

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A body starts from rest and moves with a constant acceleration of 4ms2. Calculate the velocity acquired by it after it has covered a distance of 8 m.

Step 1: Given thatInitial velocity = 0Acceleration = 4ms2.Distance= 8 m.Step 2: Formulav2-u2=2as.Step 3: Calculationv2-u2=2as.v2-0=2×4ms2×8m.v2=64.v=64.v=8ms.Step 4:Hence, Velocity = 8ms.

A body starts from rest and moves with a constant acceleration of 4 $\frac{m}{s^{2}}$ . Calculate the velocity acquired by it after it has covered a distance of 8 m.