Question

A body starts from rest and moves with a constant acceleration of $6\frac{m}{s^2}$.Calculate the distance covered by the body during 3rd second of its motion .

Answer 1

Step 1: Given data

Initial velocity (u) = 0

Acceleration (a) = $6\frac{m}{s^2}$

Need to find the distance covered by the body during 3rd second of its motion.

Step 2: Formula used

Distance travelled in the nth second = $s_{nth}=u+\frac{a}{2}(2n-1)$

Step 3: Calculation for distance covered

Distance travelled in the nth second = $s_{nth}=u+\frac{a}{2}(2n-1)$

$n=3s$

$$\begin{gathered} S_3=0+\frac{6}{2}(2\times 3-1) \\ {S}_3=3(5)m \\ {S}_3=15m \end{gathered}$$

Hence, distance covered by the body during 3rd second of its motion $15m$.