A body starts from rest and moves with a uniform acceleration. The ratio of the distance covered in the nth second to distance covered in n seconds is
A
2n−1n2
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B
1n2−1n
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C
2n2−1n
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D
2n+1n2
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Solution
The correct option is B2n−1n2 Distance travelled by a body in 'n'th second is sn=u+a2(2n−1) Distance travelled in 'n' seconds is s=un+12an2 u is zero since the body starts from rest. sns=a2(2n−1)12an2 Therefore, the ratio = sns=2n−1n2