A body starts from rest and with a uniform acceleration of 10ms−2 for 5seconds. During the next 10seconds it moves with uniform velocity the total distance travelled by the body:-
A
100m
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B
125m
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C
500m
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D
625m
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Solution
The correct option is D625m Distance covered in first 54 sec s1=0∗5+12∗10∗52=125m
Distance covered in last 10 sec s2=vt=(u+a∗5)t=(0+10∗5)10=500m